Graphic artist Boss Logic took to Instagram to showcase what actress Eiza Gonzalez could look like as Catwoman.
Take a look.
Rumors have swirled around Gonzalez becoming Catwoman as far back as 2017 when she was not only rumored to be having meetings on the Warner Bros. lot, but she also got her hair cut by celebrity stylist Buddy Porter. Porter had recently provided styling for Harley Quinn actress Margot Robbie. (Related: Will Eiza González be the Catwoman to Margot Robbie’s Harley Quinn?)
Not only did Porter give Gonzalez a new haircut, but she looked like she had just jumped out of a DC Comics comic book.
In fact, Boss Logic also mocked up Gonzalez as Catwoman when those rumors were making headlines.
Gonzalez would stir the pot surrounding Catwoman herself when she dressed up as Selina Kyle for Halloween last year. However, she has since deleted that Instagram post. (Related: Eiza Gonzalez Stirs Rumors As She Becomes Catwoman for Halloween)
It’s possible Gonzalez could be in the running to play Catwoman in the upcoming Batman film from director Matt Reeves and starring Robert Pattinson. A recent rumor indicates Reeves and Warner Bros. are looking to cast a woman of color in the role. The rumor details they were looking at Zoe Kravitz indicating they were looking for a black or mixed race actress. Gonzalez is Mexican. (Related: Rumor: Robert Pattinson’s The Batman Could Feature a Catwoman of Color or Mixed Race)
Gonzalez has made quite a name for herself in Hollywood over the years. She had a break out role in Baby Driver. Since then she’s gone on to star in Alita: Battle Angel and Fast & Furious Presents: Hobbs & Shaw. She will star in the upcoming Bloodshot film based off the Valiant Comics character alongside Vin Diesel and she will also star in Godzilla vs. Kong. (Related: Sony Taps Eiza Gonzalez, Michael Sheen, and Sam Heughan for Bloodshot Movie!)
What do you make of Boss Logic’s take on Eiza Gonzalez as Catwoman? Would you want to see the Mexican actress play Selina Kyle? Who do you want to play Catwoman?